Table of contents

  1. How to view object properties in PropertyGrid?
  2. How does List<SelectListItem> safely cast to SelectList in view
  3. How to exclude multiple properties in FluentAssertions ShouldBeEquivalentTo()

How to view object properties in PropertyGrid?

In C#, you can view object properties in a PropertyGrid control by following these steps:

  • Add a reference to System.Windows.Forms and System.Drawing assemblies if they are not already added to your project.

  • In your Windows Forms application, add a PropertyGrid control to your form. You can do this either by dragging and dropping the PropertyGrid control from the Toolbox or by creating it programmatically in your code.

  • Set the SelectedObject property of the PropertyGrid control to the object whose properties you want to view. This is typically done at runtime when you want to inspect an object's properties.

Here's a step-by-step guide to achieving this:

  • Design your Windows Forms application form:
using System;
using System.Windows.Forms;

namespace YourNamespace
{
    public partial class MainForm : Form
    {
        public MainForm()
        {
            InitializeComponent();
        }

        // Add a button to trigger the property grid display.
        private void btnShowProperties_Click(object sender, EventArgs e)
        {
            // Replace 'yourObject' with the object whose properties you want to view.
            YourObject yourObject = new YourObject();
            propertyGrid1.SelectedObject = yourObject;
        }
    }

    // Sample class representing an object with properties to be viewed in PropertyGrid.
    public class YourObject
    {
        public int Age { get; set; }
        public string Name { get; set; }
        // Add more properties as needed...
    }
}
  • In your MainForm.Designer.cs, add the PropertyGrid control definition:
private System.Windows.Forms.PropertyGrid propertyGrid1;

private void InitializeComponent()
{
    this.propertyGrid1 = new System.Windows.Forms.PropertyGrid();
    // Other controls initialization...

    // Add the PropertyGrid control to your form.
    this.Controls.Add(this.propertyGrid1);
    // Other controls arrangement and settings...
}

With these steps, when you run your Windows Forms application and click the button (e.g., btnShowProperties), the PropertyGrid control will display the properties of the YourObject object or any other object you set to the SelectedObject property. This provides a convenient way to inspect and edit properties at runtime during application development and debugging.


How does List<SelectListItem> safely cast to SelectList in view

In ASP.NET MVC and ASP.NET Core MVC, it's common to use the SelectList class to represent a list of options for a dropdown list or other HTML form control. However, sometimes you may have a list of SelectListItem objects that you want to use as the data source for a SelectList object.

Fortunately, you can safely cast a List<SelectListItem> to a SelectList object in your view using the SelectList constructor. Here's an example implementation:

@model MyViewModel

@Html.DropDownListFor(
    x => x.SelectedOption,
    new SelectList(Model.Options, "Value", "Text", Model.SelectedOption),
    "-- Select an option --"
)

In this example, we have a view that is strongly typed to a MyViewModel object. The MyViewModel class has a property called Options that is a List<SelectListItem> representing the options for a dropdown list. It also has a property called SelectedOption representing the currently selected option.

We use the DropDownListFor helper method to render a dropdown list for the SelectedOption property. The second parameter of DropDownListFor is a SelectList object that represents the options for the dropdown list. We create this SelectList object by calling its constructor with the Options property of the model as the first parameter, followed by the names of the Value and Text properties of the SelectListItem objects as the second and third parameters, respectively. Finally, we pass the SelectedOption property of the model as the fourth parameter to set the currently selected option.

By using the SelectList constructor in this way, we can safely cast a List<SelectListItem> to a SelectList object without any risk of type errors or exceptions. This allows us to easily use a list of SelectListItem objects as the data source for a dropdown list in our views.


How to exclude multiple properties in FluentAssertions ShouldBeEquivalentTo()

In FluentAssertions, you can exclude multiple properties from an object comparison using the Excluding method. Here's an example of how to exclude multiple properties in ShouldBeEquivalentTo():

using FluentAssertions;
using Xunit;

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int Age { get; set; }
    public string Email { get; set; }
}

public class PersonTests
{
    [Fact]
    public void TestPersonEquality()
    {
        // Arrange
        var expected = new Person
        {
            FirstName = "John",
            LastName = "Doe",
            Age = 30,
            Email = "[email protected]"
        };

        var actual = new Person
        {
            FirstName = "John",
            LastName = "Doe",
            Age = 30,
            Email = "[email protected]"
        };

        // Act
        // Assert
        actual.ShouldBeEquivalentTo(expected, options => options
            .Excluding(p => p.Email)
            .Excluding(p => p.Age)
        );
    }
}

In this example, we define a Person class with four properties. We define a PersonTests class with a TestPersonEquality test method that compares two Person objects using ShouldBeEquivalentTo().

We use the Excluding method to exclude the Age and Email properties from the comparison. The Excluding method takes a lambda expression that specifies the property to exclude.

By excluding multiple properties in this way, you can customize the comparison behavior to suit your needs.


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